Question

Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function? 4x + 8; 2x + 12; x^2 - 4; x^2 - 16

Answer 1

`x^2-4` because for
`x=2` it would be equal 0.

Answer 2

`4x+8\text{and}x^2-4`

Explanation:

Extraneous is the point where the solution of a function exists and it gives the value of denominator zero

In case of
`f(x)=4x+8=0`

can be the denominator in sally's function.

In case of
`f(x)=2(-2)+12=8` not the possible denominator because we are not getting zero at this point.

In case of
`f(x)=(-2)^2-4=0` is the possible denominator

in case of
`f(x)=x^2-16=(-2)^2-16=-12` is the not the possible denominator.