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How many atoms of nitrogen are represented in 2(NH4)3PO4? (My answer: C)

2

3

6

12

User Haomin
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2 Answers

6 votes
yes you would be correct due to you must multiply the superscripts with the coefficients and 2*3 would get you six nitrogens.
User Russell Uhl
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5 votes

Answer : The number of atoms of nitrogen present in
2(NH_4)_3PO_4 are, 6.

Explanation :

The given compound is,
2(NH_4)_3PO_4

The chemical name of this compound is, ammonium phosphate.

In this compound,

The number of nitrogen atoms = 6

The number of hydrogen atoms = 12

The number of phosphorous atoms = 2

The number of oxygen atoms = 8

Hence, the number of atoms of nitrogen present in
2(NH_4)_3PO_4 are, 6.

User Yuchen Zhou
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