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9. Which pair of equations below represent perpendicular lines?

A) Y = 7/8x + 12 and y = -8/7x – 8
B) Y = 5x + 15 and y = -5x + 15
C) Y = 4x + 9 and y = 4x -9
D) Y = 9 and y = 18

User Sjoseph
by
7.9k points

2 Answers

1 vote
A is correct. ...................................................
User LukeS
by
7.1k points
1 vote

Answer:


y =(7)/(8)x + 12 and
y = -(8)/(7)x - 8

Explanation:

The product of the slopes of the perpendicular lines is -1

Option 1)
y =(7)/(8)x + 12 and
y = -(8)/(7)x - 8

General equation of line :
y=mx+c

Comparing with general equation

Slope of line 1 =
(7)/(8)

Slope of line 2=
-(8)/(7)

Now product of slopes =
(7)/(8) * (-8)/(7)

=
-1

Since The product of the slopes of the perpendicular lines is -1

So,
y =(7)/(8)x + 12 and
y = -(8)/(7)x - 8 represent perpendicular lines

Option 2)
y = 5x + 15 and
y = -5x + 15

General equation of line :
y=mx+c

Comparing with general equation

Slope of line 1 = 5

Slope of line 2= -5

Now product of slopes =
5 * -5

=
-25

Since The product of the slopes of the perpendicular lines is not -1

So,
y = 5x + 15 and
y = -5x + 15 does not represents the perpendicular lines.

Option 3)
y = 4x + 9 and
y = 4x -9

General equation of line :
y=mx+c

Comparing with general equation

Slope of line 1 = 4

Slope of line 2= 4

Now product of slopes =
4 * 4

=
16

Since The product of the slopes of the perpendicular lines is not -1

So,
y = 4x + 9 and
y = 4x -9does not represents the perpendicular lines.

Option 4)
y = 9 and
y = 18

General equation of line :
y=mx+c

Comparing with general equation

Slope of line 1 = 0

Slope of line 2=0

Now product of slopes =
0 * 0

=
0

Since The product of the slopes of the perpendicular lines is not -1

So,
y = 9 and
y = 18 does not represents the perpendicular lines.

User DarkByte
by
8.2k points