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A volume of 5.0 L of gas at a temperature of 25°C is cooled to a temperature of -120°C at constant pressure. What is the new volume of the gas?

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V1 = 5L = 5000ml V2 = ?
T1 = 25°C = 25+273 T2 = -120°C
= 297K = -120+273
= 153K
By Charles Law,
V1/T1 = V2/T2
5000/297 = V2/153
By solving,
V2 = 2.576L
User Bhakti Shah
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