Question

What is the period t of the function y=3sin(4t)?

Answer 1

The period = 2pi/4 = pi2=1.571
Good luck

Answer 2

`(\pi)/(2)`

Explanation:

We are given that a function

`y=3 sin(4t)`

We have to find the period t of the given function.

To find the period of given function we will compare with general sine function equation period.

`f(x) =A sin(Bx+C)+D`

Period=
`(2\pi)/(\mid B\mid)`

By comparing we get

`\mid B\mid=4`

Substitute the value in the given formula to finding the period

Then ,we get the period t of given function=
`(2\pi)/(4)=(\pi)/(2)`

Hence, the period of given function =
`(\pi)/(2)`