Question

seawater contains approximately 3.5% NaCl by mass and has a density of 1.02g/mL. What volume of seawater conatains 1.0g of sodium

Answer 1

m(NaCl)=1.0 g
w=0.035
p=1.02 g/mL
v-?


m(NaCl)=mw
m=vp
m(NaCl)=vpw

v=m(NaCl)/(pw)

v=1.0/(1.02·0.035)=28.0 mL

Answer 2

28 mL

Step-by-step explanation:

We want to know what volume of seawater contains 1.0 g of sodium.

We know that the total amount of water mass always 3.5% corresponds to the mass of sodium.

So if the total mass of sodium is 1.0g this is equivalent to 3.5% of 100% of the mass

Calculate 100% of the mass with a simple rule of three

`3.5\% \longrightarrow 1.0g\\100\% \longrightarrow x\\x=((100)(1))/(3.5)\\ x=28.57 g`

The total mass of seawater containing 1 g of sodium is 28.57 g

Now we calculate the volume that corresponds to this mass with the density

`d=(m)/(v) \\v=(m)/(d)\\`

replace the values in the formula

`v=(28.57)/(1.02)\\ v= 28 mL`