Question

Could I have help to find x?

Answer 1

`\cfrac{16^(x+1)}{8^(2x+2)}=16 \\ \\ \cfrac{(2^4)^(x+1)}{(2^3)^(2x+2)}=2^4 \\ \\ \cfrac{2^(4x+4)}{2^(6x+6)}=2^4 \\ \\ 2^(4x+4-(6x+6))=2^4 \\ 2^(4x+4-6x-6)=2^4 \\ 2^(-2x-2)=2^4\\ \\ -2x-2=4 \\ -2x = 4+2 \\ -2x=6 \\ 2x=-6 \\ x=-6/2 \\ x=-3`

Answer 2

`(16^(x+1))/(8^(2x+2))=16\\ (2^(4x+4))/(2^(6x+6))=2^4\\ 2^(4x+4-6x-6)=2^4\\ 2^(-2x-2)=2^4\\ -2x-2=4\\ -2x=6\\ x=-3`