Question

The exact times in seconds, of four sprinters from a school track meet are as follows

Sprinter A -132.38
Sprinter B - 132.31
Sprinter C - 132.29
Sprinter D - 132.25

If the stopwatch used was precise only to the tenths place, which sprinters time is different from the others

Sprinter A B C or D

Answer 1

sprinter A

sprinters b, c, and d would all round to 132.30

b- 132.31 rounds to 132.30

c- 132.29 rounds to 132.30

d- 132.25 rounds to 132.30

*look at the last digit, less than 5 you go to lower, 5 or more you go up!

(for example 33 would round to 30, 37 would round to 40)

hope this helps!!!!!!!! <3

Answer 2

A.  would be 132.4 and the rest would be 132.3