The reaction 4al(s) + 3o2(g) --> 2al2o3(s) ?h = -3351 kj is _____, and therefore heat is _____ by the reaction

QAmmunity.org

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Oct 11, 2018 47.6k views

5 votes

The reaction 4al(s) + 3o2(g) --> 2al2o3(s) ?h = -3351 kj is _____, and therefore heat is _____ by the reaction

Chemistry
high-school

Fiona Chen asked

by Fiona Chen

8.4k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

3 votes

exothermic, release/given off

Giantriant answered Oct 15, 2018

by Giantriant

8.5k points

0 Comments

Please log in or register to add a comment.

← Prev Question Next Question →

Related questions

asked Sep 12, 2018 133k views

The reaction 4al (s) 3o2 ( g. → 2al2o3 (s) δh° = -3351 kj is ________, and therefore heat is ________ by the reaction.

Andershagbard asked Sep 12, 2018

by Andershagbard

7.7k points

Chemistry
high-school

1 answer

1 vote

133k views

asked Oct 8, 2022 124k views

NEED HELP ASAP!!! 20 POINTS!! Which of the following is an exothermic reaction? A) N2(g) + 2O2(g) → 2NO2(g) ∆H = +66.4 kJ B) 2C(s) + H2(g) +227.4 → C2H2(g) C) 4Al(s) + 3O2(g) → 2Al2O3(s) + 3351 kJ D) N2(g)

Inchara Raveendra asked Oct 8, 2022

by Inchara Raveendra

8.1k points

Chemistry
high-school

1 answer

8 votes

124k views

asked Aug 27, 2018 8.6k views

How many grams of Al2O3 are required to react completely with 1500.0 kJ of heat? 2Al2O3(s) + 3352 kJ → 4Al(s) + 3O2(g) answers 91.29 grams 2 grams 45.64 grams 1500 grams

Avi Pinto asked Aug 27, 2018

by Avi Pinto

8.8k points

Chemistry
high-school

2 answers

5 votes

8.6k views

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Related questions

Other Questions