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A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 640t. After how many seconds does the projectile take…

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 640t. After how many seconds does the projectile take…
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A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 640t. After how many seconds does the projectile take to reach its maximum height?

User Emomaliev
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1 Answer

4 votes
It will reach maximum height when
h'(t) = -32t + 640 = 0
-32t = -640
t = -640/-32 = 20 seconds
User Paul Westcott
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8.0k points
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