47.3k views
5 votes
Find the zeros of y=x^2-4x-9 by completing the square

User Zachzurn
by
7.6k points

1 Answer

5 votes

x^2-4x-9=0\\ x^2-4x+4-13=0\\ (x-2)^2=13\\ x-2=-√(13) \vee x-2=√(13)\\ x=2-√(13) \vee x=2+√(13)
User Henryabra
by
8.0k points