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A box contains 23 transistors,6 of which are defective. If 6 are selected at random, find the probility that none are defective ?

User Harriv
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1 Answer

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|\Omega|=C(23,6)=(23!)/(6!17!)=100947\\ |A|=C(17,6)=(17!)/(6!11!)=12376\\\\ P(A)=(12376)/(100947)=(1768)/(14421)
User Cfnerd
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