An angle is in standard position when its initial ray is in the x-axis, and the angle is formed by rotating the terminal ray counterclockwise, starting from the initial ray.
lets calculate all values of (525n)° for n=2, 3, 5, 6,
then express these values as 360*k+r, where k is the number of counterclockwise revolutions, and r is smaller than 360
525*2= 1050=360*2+330,
(330° is in the IV.th Quadrant, so below the x axis.)
525*3=1575=360*4+135
(135° is in the II.nd Quadrant, so above the x axis.)
525*5=2625=360*7+105
(105° is in the II.nd Quadrant, so above the x axis.)
525*6=3150=360*8+270
(270° is in the angle between the III.rd and Iv. th Quadrant, so below the x axis.)
Answer: n=2, n=6