Question

The orbital period of an object is 2 × 107 s and its total radius is 4 × 1010 m.

The tangential speed of the satellite, written in standard notation, is
Answer: ⇒ 12,560 m/s.

Answer 1

To find the tangential speed of a satellite, we use the formula vorbit = 2πr/T. By substituting the given orbital radius and period, we calculate a tangential speed of approximately 12,566 m/s.

Step-by-step explanation:

The question requires calculating the tangential speed of a satellite given its orbital period and radius. To find the tangential speed (velocity), we use the formula vorbit = 2πr/T, where r is the orbital radius and T is the orbital period. The orbital speed calculation is a fundamental application of orbital mechanics in physics, specifically within the subject of circular motion and gravitation.

• Given: Orbital period (T) = 2 × 107 s
• Given: Total radius (r) = 4 × 1010 m
• Using the formula, we calculate:

• vorbit = 2πr/T

  vorbit = 2π × (4 × 1010 m)/(2 × 107 s)

  vorbit ≈ 12,566 m/s

This calculation shows that the satellite has a tangential speed of approximately 12,566 meters per second (m/s).

Answer 2

The tangential speed of the satellite is 12,566 m/s.

Step-by-step explanation:

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