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39 votes
Hello I need some quick help with my practice question the fatser the better I have alot of practice today.

Hello I need some quick help with my practice question the fatser the better I have-example-1
User Scagood
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1 Answer

20 votes
20 votes

we have

2x+3y=12

step 1

Find the intercepts

y-intercept -----> is the value of y when the value of x is equal to zero

so

For x=0

2(0)+3y=12

solve for y

3y=12

y=4

The y-intercept is the point (0,4)

Find the x-intercept

the x-intercept is the value of x when the value of y is equal to zero

so

For y=0

2x+3(0)=12

2x=12

x=6

the x-intercept is the point (6,0)

step 2

Find the slope

we have

2x+3y=12

isolate the variable y

3y=-2x+12

divide by 3 both sides

y=(-2/3)x+4

this is the equation of the line in slope intercept form

the slope is m=-2/3

the slope is negative

step 3

Graph the line

to graph the line plot the intercepts and join then

using a graphing tool

see the attached figure

please wair

Hello I need some quick help with my practice question the fatser the better I have-example-1
User Zalogatomek
by
3.1k points