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I need help understanding how to find the dimension of a geometric figures.I need help understand how to find the value of the hypotenuse

I need help understanding how to find the dimension of a geometric figures.I need-example-1
User Florian Hermann
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1 Answer

6 votes
6 votes

We want to obtain the length of the hypotenuse.

But we must obtain x first.

Since this is a right-angle triangle, we must employ Pythagoras Theorem;


(x+10)^2=10^2+(9x)^2

The square of the hypotenuse is equal to the sum of the square of the other two sides, let's expand the equation, we obtain;


\begin{gathered} x^2+20x+100=100+81x^2 \\ \text{collect like terms to obtain} \\ 81x^2-x^2-20x+100-100=0 \\ 80x^2-20x=0 \\ 80x^2=20x \\ \text{divide both sides by 20x} \\ 4x=1 \\ x=(1)/(4)\text{ } \end{gathered}

Thus, the length of the hypotenuse is


10(1)/(4)\text{ inches}

User Ryan Thomas
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