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Which direction does the graph of the equation shown below open?

y2+16y-4x+4=0

User Kokul Jose
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2 Answers

3 votes

It opens to the right!

User Mahdi Ataollahi
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6 votes
We are asked to determine the opening of the graph of the given equation y² + 16y - 4x + 4= 0. To answer this problem, we need to transform the equation into the standard form where all variable y and variable x are in opposite side such as shown below:
y² + 16y - 4x + 4 = 0
y² + 16y = 4x - 4
y² + 16y + 64 = 4x - 4 +64
(y + 8)² = 4x + 60

Then, the graph opens to the right.
User Laaouatni Anas
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