24.9k views
0 votes
Which direction does the graph of the equation shown below open?

y2+16y-4x+4=0

User Kokul Jose
by
8.2k points

2 Answers

3 votes

It opens to the right!

User Mahdi Ataollahi
by
8.2k points
6 votes
We are asked to determine the opening of the graph of the given equation y² + 16y - 4x + 4= 0. To answer this problem, we need to transform the equation into the standard form where all variable y and variable x are in opposite side such as shown below:
y² + 16y - 4x + 4 = 0
y² + 16y = 4x - 4
y² + 16y + 64 = 4x - 4 +64
(y + 8)² = 4x + 60

Then, the graph opens to the right.
User Laaouatni Anas
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.