Question

What is the equation of the line that is parallel to the line y = -1/3 x + 4 and passes through the point (6, 5)? A: y = x + 3 B:y = x + 7 C: y = 3x – 13 D: y = 3x + 5

Answer 1

None of them are parallel but D. is perpendicular. I'm sorry if this doesn't help...

Answer 2

`y=-(1)/(3)x+7`

Explanation:

the equation of the line that is parallel to the line y = -1/3 x + 4 and passes through the point (6, 5)

`y=-(1)/(3) x+4` is the given equation.

We find out slope from the given equation. Slope is the coefficient of x

Slope of given line=
`-(1)/(3)`

slope of parallel line is same as the slope of given line

Slope of parallel line =
`-(1)/(3)`

Now we use point slope formula to get the equation of the line

`y-y_1=m(x-x_1)`, m=-1/3, x1=6 and y1=5

`y-5=-(1)/(3)(x-6)`

multiply the fraction inside the parenthesis

`y-5=-(1)/(3)x+2`

Add 5 on both sides

`y=-(1)/(3)x+7`