Question

rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8 quadratic formula x=-b+/-(sqrt)b2-4ac (fraction) 2a

Answer 1

hello :
0=2x2+3x-8
2x²+3x-8 = 0...... a =2 b =3 c = -8
the discriminant : b² - 4ac = (3)²-4(2)(-8)=9+72=81=9²
the positive solution is : x = (-b + √(b²-4ac))/2a
x = (-3+9)/4 = 6/4 = 3/2

Answer 2

For this case we have the following polynomial:

`0=2x^2+3x-8`

Using the quadratic formula we have:

`x = (-b+/-√(b^2 - 4ac))/(2a)`

Then, replacing values we have:

`x = (-3+/-√(3^2 - 4(2)(-8)))/(2(2))`

Rewriting the expression we have:

`x = (-3+/-√(9+64))/(4)`

`x = (-3+/-√(73))/(4)`

Discarding the negative root we have:

`x = (-3+√(73))/(4)`

Then, doing the calculations:

`image`

Answer:

the positive solution to the quadratic equation is:

`x = 1.39`