Question

Plz help algebra 1

Park rangers released 4 fish into a pond in year 0. Each year, there were three times as many fish as the year before. How many fish were there after x years? Write a function to represent this scenario. A. f(x) = 4(x)3 B. f(x) = 3(x)4 C. f(x) = 3(4)x D. f(x) = 4(3)x

Answer 1

f(x)=4(3) with an exponent of x on the top.

Answer 2

Answer:
`f(x) = 4(3)^x`

Explanation:

Let the function that shows the given situation is,

`f(x) = a(b)^x`

Where x is the number of years.

Initially, x = 0,

`f(0) = a(b)^0 = a`

According to question f(0) = 4

Thus, a = 4

Since, each year the number of fish is increased by 3 times,

That is, for x = 1, f(1) = 12

But,
`f(1) = a(b)^1`

⇒
`12 = 4(b)^1`

⇒ b = 3

By putting the values of a and b in the above function,

We get,
`f(x) = 4(3)^x`

Which is the required function that shows the given situation.

⇒ Option D is correct.