Question

Assuming that the density of vinegar is 1.005 g/mL, calculate the molatrity of acetic acid in vinegar from an average of 4.6% for the mass percentage of acetic acid in vinegar.

Answer 1

Acetic acid is 60.05 grams/mole. In 1 liter of vinegar or 1000 ml  there would be 0.046% of acetic acid = 46 ml x 1.005g/ml = 46.23 grams/60.05 grams= 0.77 moles per litre of vinegar.This then would be the concentration of acetic acid in for example 1 liter of vinegar.