Lets first solve the first one:
log(x+9)=log(2x−7)
Convert the logarithmic equation to an exponential equation.
10^log(x+9)=10^log(2x−7)
Remember that 10^logx=x, so
x+9=2x−7
Move values with 'x' to the right hand side.
7+9=2x-x
Combine like terms.
16=x so,
x=16
Check:
log(x+9)=log(2x−7)
If x=16
log(16+9)=log(2(16)−7)
log25=log(32−7)
log25=log25
x=16 is a solution.
Solve the second one like i solved this one, try it