Question

Find the distance between the points (2.7, 5.1) and (3, 4.7).

0.05

0.5

5

Answer 1

d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(2.7,5.1)...x1 = 2.7 and y1 = 5.1
(3,4.7)...x2 = 3, and y2 = 4.7
now we sub
d = sqrt (3 - 27/10)^2 + (47/10 - 51/10)^2
d = sqrt (3/10^2) + (-2/5^2)
d = sqrt (9/100 + 4/25)
d = sqrt 1/4
d = 1/2 or 0.5 <==

Answer 2

Answer: 0.5 units.

Explanation:

To find the distance between two points
`(x_1,y_1)\ and (x_2,y_2)` is given by distance formula :-

`D=√((x_2-x_1)^2+(y_2-y_1)^2)`

Now, the distance between the points (2.7, 5.1) and (3, 4.7) is given by :-

`D=√((3-2.7)^2+(4.7-5.1))\\\\=√((0.3)^2+(-0.4)^2)\\\\=√(0.09+0.16)\\=√(0.25)=0.5`

Hence, the distance between the points (2.7, 5.1) and (3, 4.7) is 0.5 units.