Find the longer diagonal of a parallelogram having sides of 10 and 15 and an angle measure of 60°.

Question

asked May 18, 2018 52.9k views

1 Answer

Ravi Saroch · Answer 1 · 2018-05-23T16:38:02+0000

Angle alfa = A = 60°
Angle beta = B = 360° - 2A = 240°
Diagonal = d
sides of parallelogram are a and b

d² = a² + b² - 2ab × cosB