Question

Let m,n,p, and q represent nonzero positive integers. find a number in terms of m,n,p, and q that is halfway between m/n and p/q.

Answer 1

This is the same as averaging. You add them and divide by 2.

((m/n) + (p/q))/2 would be a number in between m/n and p/q.

Do note that n and q must be nonzero, but luckily that is a given.

Answer 2

it is given that,m,n,p, and q represent nonzero positive integers.

A number between a and b is given by

`(a+b)/(2)`

where, a and b are rational numbers ,having denominator ≠0.

A number between

`(m)/(n) \text{and} (p)/(q) \text{is equal to}\\\\=((m)/(n) + (p)/(q))/(2)\\\\=(mq+np)/(2nq)`