Question

Write an equation in point-slope form of the line that passes through the given point and has the given slope. (4, -5); m=6. Then simplify the equation to slope intercept form

Answer 1

The general equation of a straight line is y = mx + c

m is the gradient , c is the intercept, y and x are two points on the straight line

To obtain equation of a line using a slope and one point form; use the slope and the point coordinate to obtain the intercept

Then substitute the intercept and the slope in y=mx + c to get your equation

y = mx + c

y = -5, x = 4 , m= 6

-5 = 6 x 4 + c

-5 = 24 + c

collect like terms

- 5 - 24 = c

c = -29

Then the equation of the line is

y = 6x + (-29)

y = 6x - 29