Question

A target has a bull’s-eye with a diameter of 2 inches. the outer ring is 1 inch wide. what is the area of the outer ring?

Answer 1

The diameter of the outer ring will be 4 inches since it extends one inch beyond the bull's eye from either side. See the attached image for clarification.

The area of the outer ring can be expressed as:

`Area_(outerring) = Area_(outercircle) - Area_(bullseye)`
This is because we need to take into account of the space taken up by the bullseye.

Now we set up our equation:

`Area_(outerring) = \pi r^(2)_(outercircle) - \pi r^(2)_(bullseye)`

Now plug and solve:

`Area_(outerring) = \pi 2^(2) - \pi 1^(2)`

`Area_(outerring) = 4\pi - \pi`

`Area_(outerring) = 9.42477796`