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What is the units of k in the following expression: rate = k[A][B]?

A) s^-1
B)M^-1 s^-1
C)M^-2 s^-1
D)M

2 Answers

6 votes
What is the units of k in the following expression: rate = k[A][B]?

A) s^-1
B)M^-1 s^-1
C)M^-2 s^-1
D)M

ans: B
User Juan Riaza
by
8.2k points
2 votes

Answer : The correct option is, (B)
M^(-1)s^(-1)

Step-by-step explanation:

Rate of reaction : It is defined as the rate of change in concentration of reactant or product with respect to time.

The given rate expression is,


Rate=k[A][B]

From this expression we conclude that the power of concentration of reactant A and B are 1, 1. That means it is a second order reaction.

The formula for determining the unit of 'k' is:


\text{Unit}=((Concentration)^(1-n))/(Time)

where, n = order of reaction

The unit of concentration is, M or mole/L

The unit of time is, second or 's'.

When n = 0

The unit of 'k' =
((M)^(1-0))/(s)=Ms^(-1)

When n = 1

The unit of 'k' =
((M)^(1-1))/(s)=s^(-1)

When n = 2

The unit of 'k' =
((M)^(1-2))/(s)=M^(-1)s^(-1)

and so on.....

Therefore, the unit of 'k' of the following expression is,
M^(-1)s^(-1)

User Amna Ahmed
by
8.6k points