Question

The input work done on a machine is 9.63 × 103 joules, and the output work is 3.0 × 103 joules. What is the percentage efficiency of the machine?

Answer 1

Answer: The percentage efficiency of the machine is 31.15 %.

Step-by-step explanation:

Input work done =
`9.63* 10^3 joules`

Output work done =
`3.0* 10^3 joules`

The efficiency of the machine =
`(W_(Out))/(W_(In))* 100`

`efficiency \%=(3.0* 10^3 joules)/(9.63* 10^3 joules)* 100=31.15\%`

The percentage efficiency of the machine is 31.15 %.

Answer 2

Input work = 9.63×10³ J.
Output work = 3.0×10³ J

By definition,
Efficiency = (Output work)/(Input work)
= (3.0×10³)/(9.63×10³)
= 0.31 = 31%

Answer: 31%