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What is the standard form of (2-4i)(3+5i)/(3+i)?

User Knowbody
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Answer:

AKA Letter Choice E on Plato!!

User Aelius
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((2-4i)(3+5i))/(3+i)=\\ (6+10i-12i+20)/(3+i)=\\ (26-2i)/(3+i)=\\ ((26-2i)(3-i))/(9+1)=\\ (78-26i-6i-2)/(10)=\\ (76-32i)/(10)=\\ (38)/(5)-(16)/(5)i
User Nuch
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