Question

What are the values of a, b, and c in the quadratic equation -2x^2+4x-3=0

Answer 1

`a=-2\\b=4\\c=-3`

Explanation:

We know that a standard form of equation in quadratic is

`ax^2+bx+c=0`

We are given an equation as

`-2x^2+4x-3=0`

To find a,b and c, it is sufficient to compare the given equation with std form

Comparing
`-2x^2+4x-3=0` with
`ax^2+bx+c=0`

equate the coefficients of corresponding terms.

So we have

`a=-2\\b=4\\c=-3`