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Use the formulas a = x 2 – y 2, b = 2xy, c = x 2 + y 2 to answer this question. One leg of a right triangle has length 11 and all sides are whole numbers. Find the lengths of the other two sides.

The other leg = ______ a0 and the hypotenuse =_______ a1

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Let the legs of the right triangle be a and b and the hypothenus be c, then by the pythagoras theorem

a^2+b^2=c^2

Given that

a =x^2-y^2

Let a = 11, then

x^2-y^2=11

By trial and error, we can find that the value of x = 6 and the value of y = 5.
i.e.

x^2-y^2=6^2-5^2=36-25=11

Thus,
b = 2(6)(5) = 60
and

x^2+y^2=6^2+5^2=36+25=61

Therefore, the other leg = 60 and the hypotenuse = 61.
User Nadav Finish
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