Question

An archery target is shown. The length of a side of the Inner square is 4 m and the length of a side of the outer square is 7 m If an arrow hits the target at random, what Is the probability that it hits the inner square? Round to the nearest percent.

Answer 1

answer is: 33 %

Answer 2

This is the concept of the probability and statistics. To get the probability of hitting the inner circle we proceed as follows;
P(inner square)=[area of inner circle]/[area of outer square]
area of inner square will be:
Area=length*width
Area=4*4=16 m^2
Area of outer square:
Area=7*7=49 m^2
thus;
P(hitting inner square)=16/49=0.3265=32.65%