Question

a television of mass 8kg sits on a table the coefficient of static friction between the table and television is .48 what is the minimum applied force that will cause the television to slide

Answer 1

Th normal reaction between the television and the table is
N = (8 kg)(9.8 m/s²) = 78.4 N

The static coefficient of friction is μ = 0.48.

When the television is about to slide on the table, the applied force should overcome the force due to static friction.

The applied force should be at least
F = μN
= 0.48*78.4
= 37.632 N

Answer: 37.6 N (nearest tenth)