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Which are real zeroes of this function? x3 + 2x2 – 9x – 18

2 Answers

7 votes

Answer:

Option B

Explanation:

the real zeroes are -2,-3 and 3

User Arnaud Valmary
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5 votes
Try putting x = -2:-

f(-2) = -8 + 2(-2)^2 -9(-2) - 18 = -8 + 8 + 18 -18 = 0

so one zero is -2

as the last term is -18 it is also worth trying to see is 3 , -3 or 9 or -9 are roots ( by the Rational Roots Theorem)

in fact f(3) = 0 and f(-3) = 0 also


So the real zeroes are -2,-3 and 3.
User Blackbourna
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