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In ABC, AB=3 and AC=9 find m<B to the nearest degree
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In ABC, AB=3 and AC=9 find m<B to the nearest degree

In ABC, AB=3 and AC=9 find m<B to the nearest degree-example-1
User Giladbu
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2 Answers

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Answer: 72° (nearest degree)

User Cotten
by
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5 votes
By definition,
tanB = opposite/adjacent = 9/3 = 3

From the calculator,
B = arctan(3) = 71.6°

Answer: 72° (nearest degree)
User Brunovianarezende
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8.9k points
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