f(x) = (x+3)(x-2) → f(x) = x² + x - 6
1st : The coefficient a > 0, the parabola opens upward,
2nd: The x-= intercepts are x = - 3 & x= +2 ( the values that render f(x) = 0
3rd: For x = 0, y = - 6 (this is y intercept)
The only figure that corresponds to those specifications is the 1st graph