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What will be the n-factor for Ba (MnO4)2 in acidic medium?(where it behaves as an oxidant)

User Kelketek
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Ba(MnO₄)₂ → Ba²⁺ + 2MnO₄⁻

MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O n=5
User Ravi Garg
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