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Solve the system y = 2x – 4 and y = (x – 1)2 – 5

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hello :
y = 2x – 4 ...(1)
y = (x – 1)² – 5....(2)
subsct in (2) :
2x - 4 = (x – 1)² – 5
2x - 4 = x² -2x +1 -5
x² -4x =0
x(x-4) =0
x= 0 or x = 4
if : x = 0 y = 2(0) -4 = -4
if : x = 4 y = 2(4)-4 = 4
two solutions : (0, 4) , (4, 4 )
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