Question

Consider this reaction and answer the questions:

KCIO3->KCL+O2

What is the oxidation number of chlorine in the reactant state?
What is the oxidation number of oxygen in the reactant state?
What is the oxidation number of potassium in the reactant state?
What is the oxidation number of chlorine in the product state?
What is the oxidation number of oxygen in the product state?
What is the oxidation number of potassium in the product state?

Answer 1

2KCl⁺⁵O₃ → 2KCl + 3O₂⁰

reagents
Cl +5
O -2
K +1

products
Cl 0
O -2
K +1

Answer 2

1) +5

2) -2

3) +1

4) -1

5) 0

6) +1

Step-by-step explanation:

The rules to determine oxidation number are

a) The oxidation number of alkali metals is +1 (except in super oxides or peroxides).

b) the oxidation number of oxygen is -2 (except in super and peroxide or compounds with fluorine or with itself)

1) the oxidation number of chlorine in the reactant state: KClO₃:

+1 + x + 3(-2) = 0

x = oxidation number of chlorine =+5

2) The oxidation number of oxygen in the reactant state: -2 as it is a normal oxide.

3) The oxidation number of potassium in the reactant state: +1

4) The oxidation number of chlorine in the product state: -1

5 The oxidation number of oxygen in the product state: 0

The compound with itself.

6) The oxidation number of potassium in the product state+ +1 (alkali metal)