Question

The magnetic field at a distance of 2 cm from a current-carrying wire is 4 µT. Find the magnetic field at a distance of 1 cm from the wire.Group of answer choices2 µT4 µT6 µT8 µT

Answer 1

Given:

The magnetic field is

`B=\text{ 4 }\mu T`

when the distance is d = 2 cm.

To find the magnetic field when the distance is d' = 1 cm

Step-by-step explanation:

The relation between magnetic field and distance is

`\begin{gathered} B=(\mu_0I)/(2\pi d) \\ B=(k)/(d) \end{gathered}`

Let the k be any arbitrary constant.

`\begin{gathered} k=\text{ Bd} \\ =4\text{ }*2 \\ =8\text{ cm }\mu T \end{gathered}`

On substituting the values, the magnetic field will be

`\begin{gathered} B^(\prime)=(k)/(d) \\ =\frac{8\text{ cm }\mu T}{1\text{ cm}} \\ =\text{ 8 }\mu T \end{gathered}`

Final Answer: The magnetic field is 8 micro Tesla when the distance is 1 cm.