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Edward plans to put $75 into a savings account. He can place his money into an account represented by b(x) = 7x + 75, or into another account represented by c(x) = 75(1.06)x. Which account has the highest value in 2 years? Which account has the highest in 12 years?

A.) c(x) has the highest value in 2 years; c(x) has the highest value in 12 years

B.) b(x) has the highest value in 2 years; b(x) has the highest value in 12 years

C.) c(x) has the highest value in 2 years; b(x) has the highest value in 12 years

D.) b(x) has the highest value in 2 years; c(x) has the highest value in 12 years

User Maurox
by
7.9k points

2 Answers

3 votes

Answer: B

Step-by-step explanation: b(x) is highest all the time

User Judereid
by
7.9k points
2 votes

Let

x------> the time in years

b(x)----> the value in dollars of a saving account

c(x)----> the value in dollars of another account

we know that


b(x)=7x+75


c(x)=75(1.06)^(x)

Step 1

Find the value of each account for
x=2\ years


b(2)=7*2+75=\$89


c(2)=75(1.06)^(2)=\$84.27

so


b(2) > c(2)----> b(x) has the highest value in
2 years

Step 2

Find the value of each account for
x=12\ years


b(12)=7*12+75=\$159


c(12)=75(1.06)^(12)=\$150.91

so


b(12) > c(12)----> b(x) has the highest value in
12 years

therefore

the answer is the option B

b(x) has the highest value in
2 years; b(x) has the highest value in
12 years



User Dzinx
by
8.3k points

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