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The formula v=√64h can be used to find the velocity v in feet per second of an object that has fallen h feet. When the velocity of an object reaches 38 feet per second, how far has it fallen?

A) 30.59 feet
B) 49.32 feet
C) 306.93 feet
D) 22.56 feet

2 Answers

4 votes
v = sqrt 64h

38 = sqrt 64h
38^2 = 64h
1444 = 64h
1444/64 = h
22.56 = h <===

User Andrej Soroj
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8.2k points
3 votes

Answer:

The velocity of an object reaches 38 feet per second,then the height it has fallen is:

D) 22.56 feet

Explanation:

The formula that is used to relate the velocity and height of of an object by:


v=√(64h)

where v is the velocity of the object and h is the height of the object how far it has fallen.

Now, we are asked to find the value of h when v=38

Hence, we get:


38=√(64h)

on squaring both side of the equation we get:


(38)^2=64h\\\\i.e.\\\\h=((38)^2)/(64)\\\\i.e.\\\\h=(1444)/(64)\\\\i.e.\\\\h=22.5625

Hence, the correct answer is: Option: D

User Woody
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8.9k points