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When a driver presses the brake pedal, his car stops with an acceleration of -8.7 m/s2. How far will the car travel while coming to a complete stop if its initial speed was 10 m/s?

2 Answers

2 votes

Answer:

5.74 m

Step-by-step explanation:

We can solve the problem by using the following SUVAT equation:


v^2 -u^2 =2aS

where

v is the final velocity (in this case, v=0, since the driver comes to a stop)

u is the initial velocity (in this case, u=10 m/s)

a is the acceleration (in this case, a=-8.7 m/s^2)

S is the distance covered by the car

Re-arranging the equation and substituting the numbers given by the problem, we can find S:


S=(-u^2)/(2a)=(-(10 m/s)^2)/(2(-8.7 m/s^2))=5.74 m

User AndreiM
by
8.1k points
4 votes
we are given with the initial velocity and the deceleration rate and is asked in the problem the distance the car travels until the car stops. we use the kinematic equation v 2 =v 0 2 +2aΔx where vo = 10 m/s , a = -8.7m/s^2 and v = 0

0 = 100 - 2* 8.7*
Δx
Δx = 5.75 m.
User Rakesh Adhikesavan
by
7.5k points