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Dave's sister baked $3$ dozen pies of which half contained chocolate, two thirds contained marshmallows, three-fourths contained cayenne, and one-sixths contained salted soy nuts. What is the largest possible number of pies that had none of these ingredients?

User Emil H
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2 Answers

1 vote

Answer:

its 9

Explanation:

im using aops answer said 9

User Sujithvm
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6 votes
Number of pies = 3×12 = 36

Pies contained chocolate =
(1)/(2)×36 = 18
Pies contained marshmallows =
(2)/(3)×36 = 24
Pies contained cayenne =
(3)/(4)×36 = 27
Pies contained soy nut =
(1)/(6)×36 = 6

Pies that don't contain any of these 36-(18+24+27+6) = 25 pies
User Mayur Kukadiya
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