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Dave's sister baked $3$ dozen pies of which half contained chocolate, two thirds contained marshmallows, three-fourths contained cayenne, and one-sixths contained salted soy nuts. What is the largest possible
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May 12, 2018
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Dave's sister baked $3$ dozen pies of which half contained chocolate, two thirds contained marshmallows, three-fourths contained cayenne, and one-sixths contained salted soy nuts. What is the largest possible number of pies that had none of these ingredients?
Mathematics
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Emil H
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Answer:
its 9
Explanation:
im using aops answer said 9
Sujithvm
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May 13, 2018
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Number of pies = 3×12 = 36
Pies contained chocolate =
×36 = 18
Pies contained marshmallows =
×36 = 24
Pies contained cayenne =
×36 = 27
Pies contained soy nut =
×36 = 6
Pies that don't contain any of these 36-(18+24+27+6) = 25 pies
Mayur Kukadiya
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May 17, 2018
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Mayur Kukadiya
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