Question

Dave's sister baked $3$ dozen pies of which half contained chocolate, two thirds contained marshmallows, three-fourths contained cayenne, and one-sixths contained salted soy nuts. What is the largest possible number of pies that had none of these ingredients?

Answer 1

its 9

Explanation:

im using aops answer said 9

Answer 2

Number of pies = 3×12 = 36

Pies contained chocolate =
`(1)/(2)`×36 = 18
Pies contained marshmallows =
`(2)/(3)`×36 = 24
Pies contained cayenne =
`(3)/(4)`×36 = 27
Pies contained soy nut =
`(1)/(6)`×36 = 6

Pies that don't contain any of these 36-(18+24+27+6) = 25 pies