Answer: Teacher would require 1500mL of solution for the whole class.
Step-by-step explanation:
It is given that 50mL of a solution is required by 1 student to perform 1 set of titration and each student does the experiment 2 times, so every student would require (50 × 2) = 100mL of the solution.
There are in total 15 students in the class, so total volume of the solution required by the class will be = ( 15 × 100) = 1500mL
Hence, teacher would require 1500mL of solution for the whole class.