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What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 49 rpm (revolutions per minute) if the wheel's diameter is 38 cm ?
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What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 49 rpm (revolutions per minute) if the wheel's diameter is 38 cm ?

User Iansen
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1 Answer

4 votes
Radial acceleration is a=v^2/r. For circular motion, the tangential velocity is v=2pi*r*f.
f is in Hz so 49/60=0.81667Hz.
radius in meters is 0.38m
So a=(2pi*f)^2*r = 10m/s^2
User Abbas Galiyakotwala
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