Question

I NEED HELP NOW!!!

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The calorimeter and the water have a combined mass of 250.0 g and an overall specific heat of 1.035 cal/g•°C. The initial temperature of the calorimeter is 10.00°C. The system reaches a final temperature of 11.08°C when the metal is added. What is the specific heat of the metal???

Answer 1

At equilibrium, both metal and calorimeter have the same temperature. By conservation of energy, the energy lost by the metal is gained by the calorimeter:


`heat\,gain\,by\,calorimeter=heat\,loss\,by\,metal`

`250.0g* 1.035cal/g/C * (11.08-10)C = 50.00g* C_(v)* (45-11.08)C`
Where
`C_(v)` is the specific heat of the unknown metal. Solving this gives us the specific heat of the metal:

`C_(v)=0.165cal/g/C`

Answer 2

Answer: 0.1648

:) :]