Question

5.00 mol of gas occupy a volume of 112 L at a pressure of 1.00 atm. What is the kelvin temperature of the gas?

Answer 1

n = 5 moles, V = 112 L, P = 1.00 atm
PV = nRT --> T = PV/nR
T = (1)(112) / (5)(.0821)
T = 272.8 K = 273 K

Answer 2

273 K

Step-by-step explanation:

We can assume an ideal gas and use the ideal gas law:

`P*V=n*R*T`

Where P is the pressure in Pascal, V is the volume in m^3, n is the number of moles, R is the universal gas constant in J/mol.K and T is the temperature in K.

We must convert the values to SI units.

1 L = 0.001 m^3

1 atm = 101325 Pa

Therefore the Pressure and Volume can be calculated as:

`V=112*0.001=0.112`

`P=1*101325=101325`

Therefore the Temperature in Kelvin can be determine from the ideal gas law:

`T=(P*V)/nR=(101325*0.112)/(5*8.314)=273`