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What is the solutions of x2 = –13x – 4

User Liliana
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1 Answer

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x^(2) =-13x-4 \\ x^2+13x+4=0 \\ D=b^2-4ac=13^2-4*1*4=169-16=153 \\ x_(1,2)= (-bб √(D) )/(2a) \\ \\ x_1= (-13- √(153) )/(2)=- (13- 3√(17) )/(2) \\ \\ x_2= (-13+ √(153) )/(2)= (3 √(17) -13)/(2)
User Sameer Arora
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